8y^2+70=48y

Solution for 8y^2+70=48y equation:

8y^2+70=48y

We move all terms to the left:

8y^2+70-(48y)=0

a = 8; b = -48; c = +70;
Δ = b2-4ac
Δ = -482-4·8·70
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-8}{2*8}=\frac{40}{16}
=2+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+8}{2*8}=\frac{56}{16}
=3+1/2
$